Kako pretvoriti y = 2y ^ 2 + 3x ^ 2-2xy u polarnu jednadžbu?

Odgovor:

# R = sintheta / (2sin ^ 2 theta + 3cos ^ 2 theta-sin (2 theta)) *

Za to će nam trebati:

# x = rcostheta #

# Y = rsintheta #

# Rsintheta = 2 (rsintheta) ^ 2 + 3 (rcostheta) ^ 2-2 (rcostheta) (rsintheta) #

# Rsintheta = 2r ^ 2sin ^ 2 theta + 3s ^ 2cos ^ 2 theta-2r ^ 2costhetasintheta #

# Sintheta = 2rsin ^ 2 theta + 3rcos ^ 2 theta-2rcosthetasintheta #

# Sintheta = 2rsin ^ 2 theta + 3rcos ^ 2 theta-rsin (2 theta) #

# Sintheta = r (2sin ^ 2 theta + 3cos ^ 2 theta-sin (2 theta)) *

# R = sintheta / (2sin ^ 2 theta + 3cos ^ 2 theta-sin (2 theta)) *