Što je obrnuto od f (x) = 3 ^ (x ^ 2-3x)?

Što je obrnuto od f (x) = 3 ^ (x ^ 2-3x)?
Anonim

Odgovor:

# Y = 3/2 + -sqrt (log_3x + 9/4) #

Obrazloženje:

# Y = 3 ^ (x ^ 2-3x) #

drzak #x# i # Y #.

# X = 3 ^ (y ^ 2-3y) #

Riješite za # Y #.

# Log_3x = log_3 (3 ^ (y ^ 2-3y)) *

# Log_3x = y ^ 2-3y #

# Log_3x + 9/4 = y ^ 2-3y + 9/4 #

# Log_3x + 9/4 = (y-3/2), 2 # ^

# + - SQRT (log_3x + 9/4) = y-3/2 #

# Y = 3/2 + -sqrt (log_3x + 9/4) #