Pojednostavite: {(6 ^ 6) ^ 4 -: (6 ^ 7) ^ 0 xx [(6 ^ 2) ^ 3] ^ 2} ^ 2 -: {[(6 ^ 3) ^ 5xx (6 ^ 2) ^ 3] ^ 3: [(6 ^ 3) ^ 3] ^ 4} ^ 2?

$Pojednostavite: {(6 ^ 6) ^ 4 -: (6 ^ 7) ^ 0 xx [(6 ^ 2) ^ 3] ^ 2} ^ 2 -: {[(6 ^ 3) ^ 5xx (6 ^ 2) ^ 3] ^ 3: [(6 ^ 3) ^ 3] ^ 4} ^ 2?$

Odgovor:

#6^18#

Obrazloženje:

# {(6 ^ 6) ^ 4 -:(6 ^ 7) ^ 0xx (6 ^ 2) ^ 3 ^ 2 ^ 2} -: {(6 ^ 3) ^ 5xx (6 ^ 2) ^ 3 ^ 3 -: (6 ^ 3) ^ 3 ^ 4 ^ 2} #

= # {6 ^ (24) -: 6 ^ 0xx6 ^ (12)} ^ 2 -: {6 ^ (15) xx6 ^ 6 ^ 3 -: 6 ^ 9 ^ 4 ^ 2} #

= #{6^(24-0+12)}^2-:{6^(15+6)^3-:6^36}^2#

= #{6^(36)}^2-:{6^(21)^3-:6^36}^2#

= #6^(72)-:{6^(63)-:6^36}^2#

= #6^(72)-:{6^(63-36)}^2#

= #6^(72)-:{6^(27)}^2#

= #6^(72)-:6^(54)#

= #6^(72-54)#

= #6^18#

Pojednostavite (1 - cos theta + sin theta) / (1+ cos theta + sin theta)?

= sin (theta) / (1 + cos (theta)) (1-cos (theta) + sin (theta)) / (1 + cos (theta) + sin (theta)) = (1-cos (theta) + sin (theta)) * (1 + cos (theta) + sin (theta)) / (1 + cos (theta) + sin (theta)) ^ 2 = ((1 + sin (theta)) ^ 2-cos 2 (theta)) / (1 + cos ^ 2 (theta) + sin ^ 2 (theta) +2 sin (theta) +2 cos (theta) + 2 sin (theta) cos (theta)) = ((1+ sin (theta)) ^ 2-cos ^ 2 (theta)) / (2 + 2 sin (theta) +2 cos (theta) + 2 sin (theta) cos (theta)) = ((1 + sin (theta)) ) ^ 2-cos ^ 2 (theta)) / (2 (1 + cos (theta)) + 2 sin (theta) (1 + cos (theta)) = (1/2) ((1 + sin (theta)) ) ^ 2-cos ^ 2 (theta)) / ((1 + cos (theta)) (1 + sin (

Pomnožite zagrade i pojednostavite (2sqrta-3sqrtb) (sqrta + sqrtb)?

2a-sqrt (ab) -3b (2sqrt-3sqrt b) (sqrt a + sqrt b) (2sqrta * sqrta) -3sqrtb * sqrta) + (2sqrta * sqrtb) - (3sqrtb * sqrtb) = 2a-3sqrt (ab ) + 2sqrt (ab) -3b = 2a-sqrt (ab) -3b

Kako pojednostavite ((x ^ 2-y ^ 2) (x ^ 2 + xy + y ^ 2)) / ((x ^ 3-y ^ 3) (x ^ 2 + 2xy + y ^ 2))?

To pojednostavljuje na 1 / (x + y). Prvo, faktor donjih desnih i gornjih lijevih polinoma pomoću posebnih binomnih slučajeva faktoringa: boja (bijela) = (boja (zelena) ((x ^ 2-y ^ 2)) (x ^ 2 + xy + y ^ 2)) / ((x ^ 3-y ^ 3) boja (plava) ((x ^ 2 + 2xy + y ^ 2))) = (boja (zelena) ((xy) (x + y)) (x ^ 2 + xy + y ^ 2)) / ((x ^ 3-y ^ 3) boja (plava) ((x + y) (x + y))) Poništite zajednički faktor: = (boja (zelena) ((xy) boja (crvena) cancelcolor (zeleno) ((x + y))) (x ^ 2 + xy + y ^ 2)) / ((x ^ 3-il ^ 3) boja (plava) ((x + y) Boja (crveno) poništavanje boje (plavo) ((x + y)))) = (boja (zelena) ((xy)) (x ^ 2 + xy + y ^ 2)) / ((x ^