Kako pojednostavljujete (4 + sqrt50) - (3-sqrt (8))?

Kako pojednostavljujete (4 + sqrt50) - (3-sqrt (8))?
Anonim

Odgovor:

# = 1 + # 7sqrt2

Obrazloženje:

# Sqrt50 = 5sqrt2 # i # Sqrt8 = 2sqrt2 #

Jednadžba postaje # (4 + 5sqrt2) - (3-2sqrt2) #

# = 4 + + 5sqrt2-3 2sqrt2 #

# = 1 + # 7sqrt2

Odgovor:

# (4 + sqrt50) - (3-sqrt8) = 1 + # 7sqrt2

Obrazloženje:

# (4 + sqrt50) - (3-sqrt8) #

# Sqrt50 = sqrt (25xx2) = sqrt25xxsqrt2 = 5sqrt2 #

# Sqrt8 = sqrt (4xx2) = sqrt4xxsqrt2 = 2sqrt2 #

# (4 + sqrt50) - (3-sqrt8) = (4 + 5sqrt2) - (3-2sqrt2) #

# = 4 + + 5sqrt2-3 2sqrt2 #

# = (4-3) + (+ 5sqrt2 2sqrt2) #

# = 1 + # 7sqrt2

# (4 + sqrt50) - (3-sqrt8) = 1 + # 7sqrt2