Kako razlikovati cos (1-2x) ^ 2?

Odgovor:

# Dy / dx = 4cos (1-2x) sin (1-2x) #

Obrazloženje:

Prvo, neka #cos (1-2x) = u #

Tako, # Y = z ^ 2 #

# Dy / dx = (dy) / (du) + (du) / (dx) #

# (Dy) / (du) = 2u #

# (Du) / (dx) = D / DX cos (1-2x) = D / DX cos (v) #

# (Du) / (dx) = (du) / (DV) + (dv) / (dx) #

# dy / dx = (dy) / (du) * (du) / (dv) * (dv) / (dx) #

# (Du) / (DV) = - sin (v) *

# (Dv) / (dx) = - 2 #

# Dy / dx = 2u * -sin (v) * - 2 #

# Dy / dx = 4usin (v) *

# Dy / dx = 4cos (1-2x) sin (1-2x) #