Što je prvi derivat i drugi derivat 4x ^ (1/3) + 2x ^ (4/3)?

Odgovor:

# (d y) / (d x) = 4/3 * x ^ (- 2/3) + 8/3 * x ^ (1/3) "(prvi derivat)" #

# (d ^ 2 y) / (d t ^ 2) = 8/9 * x ^ (- 2/3) (- x ^ -1 + 1) "(drugi derivat)" #

# Y = 4x ^ (1/3) + 2x ^ (4/3) #

# (d y) / (d x) = 1/3 * 4 * x ^ ((1 / 3-1)) + 4/3 * 2x ^ ((4 / 3-1)) #

# (d y) / (d x) = 4/3 * x ^ (- 2/3) + 8/3 * x ^ (1/3) "(prvi derivat)" #

# (d ^ 2 y) / (dt ^ 2) = - 2/3 * 4/3 * x ^ ((- 2 / 3-1)) + 8/3 * 1/3 * x ^ ((1 / 3-1)) #

# (d ^ 2 y) / (d t ^ 2) = - 8/9 * x ^ ((- 5/3)) + 8/9 * x ^ ((- 2/3) #

# (d ^ 2 y) / (d t ^ 2) = 8/9 * x ^ (- 2/3) (- x ^ -1 + 1) "(drugi derivat)" #