Odgovor:
Pogledaj ispod
Obrazloženje:
# 3sec ^ 2thetatan ^ 2 theta + 1 = sec ^ 6theta-tan ^ 6theta #
Desna strana# = Sec ^ 6theta-ten ^ 6theta #
# = (S ^ 2 theta) ^ 3- (2 theta tan ^) ^ 3 #-> koristiti razliku od dvije kocke formula
# = (sek ^ 2 theta-tan ^ 2theta) (s ^ 4ta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) #
# = 1 * (sek ^ 4 theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) #
# = Sec ^ 4theta + sek ^ 2thetatan ^ 2 theta + tan ^ 4theta #
# = sek ^ 2 theta sek ^ 2 theta + sec ^ 2tetatan ^ 2 theta + tan ^ 2tea tan ^ 2 theta #
# = sek ^ 2 theta (tan ^ 2 theta + 1) + sec ^ 2thetatan ^ 2theta + tan ^ 2theta (sec ^ 2theta-1) #
# = Sec ^ 2thetatan ^ 2 theta + sec ^ 2 theta + sek ^ 2thetatan ^ 2 theta + sek ^ 2thetatan ^ 2thetatan ^ 2 theta #
# = Sec ^ 2thetatan ^ 2 theta + sek ^ 2thetatan ^ 2 theta + sek ^ 2thetatan ^ 2 theta + sek ^ 2thetatan ^ 2 theta #
# = 3sec ^ 2thetatan ^ 2theta + 1 #
#=# Lijeva strana