Odgovor:
# = 19/7 p = 75/7 q = 25/7 #
Obrazloženje:
zvanje
# F_1 (x) = x ^ 3-3x ^ 2 + 2x-3 #
# F_2 (x) = x ^ 2-5x + a #
mi to znamo
# F_1 (x) = q_1 (x) (x-2) + p # i
# F_2 (x) = q_2 (x) (x-2) + q #
tako
# f_1 (2) = 8a-12 + 4-3 = p #
# F_2 (2) = 10 + 4a-a = q # I također
# P = 3 Q #
Rješavanje
# {(8a-11-p), (5a-10-q), (p = 3 Q)} #
dobivamo
# = 19/7 p = 75/7 q = 25/7 #