Možete početi racionalizacijom:
# (Sqrt (1 + x) + sqrt (1-x)) / (sqrt (1 + x) -sqrt (1 x)) × (sqrt (1 + x) + sqrt (1-x)) / (sqrt (1 + x) + sqrt (1-x)) = #
# = (Sqrt (1 + x) + sqrt (1-x)) ^ 2 / (2 x) = #
# = ((1 + x) + 2sqrt (1 + x) sqrt (1-x) + (1-x)) / (2 x) = #
# = (2 + 2sqrt (1-x ^ 2),) / (2 x) = #
# = (1 + sqrt (1-x ^ 2),) / (x) = #
Uvrštavanjem: # x = sqrt (3) / 2 # dobivate:
# = (1 + sqrt (1- 3/4)) / (sqrt (3) / 2) = (1 + 1/2) * (2 / sqrt (3)) = #
# = 3/2 * 2 / sqrt (3) = 3 / sqrt (3) = 3 / sqrt (3) * sqrt (3) / sqrt (3) = sqrt (3) *
Nadam se da je to ono što vam je potrebno!:-)
